Upon completing this lesson, you will be able to:
In our study of limits, we have seen that direct substitution is the easiest way to evaluate a limit. However, this method fails when it results in a mathematically ambiguous expression. These expressions are called indeterminate forms. They are "indeterminate" because their value cannot be determined from the form alone.
The two primary indeterminate forms are:
Encountering an indeterminate form does not mean the limit does not exist. It is a signal that we must use a more powerful technique to analyze the behavior of the functions involved.
L'Hôpital's Rule (pronounced "Lo-pee-tal's") provides a powerful and direct method for resolving the indeterminate forms $\frac{0}{0}$ and $\frac{\infty}{\infty}$. The rule states that if the limit of a quotient of two functions is indeterminate, we can often find the limit by taking the derivative of the numerator and the derivative of the denominator separately.
Suppose that $f$ and $g$ are differentiable functions and that $g'(x) \neq 0$ near $c$ (except possibly at $c$). If the limit $\lim_{x \to c} \frac{f(x)}{g(x)}$ produces an indeterminate form of type $\frac{0}{0}$ or $\frac{\infty}{\infty}$, then:
$$ \lim_{x \to c} \frac{f(x)}{g(x)} = \lim_{x \to c} \frac{f'(x)}{g'(x)} $$
Provided that the limit on the right side exists or is $\infty$ or $-\infty$. This rule also applies to limits as $x \to \infty$ or $x \to -\infty$.
Important: This is not the Quotient Rule. We differentiate the numerator and denominator independently of each other.
Evaluate the limit:
$$ \lim_{x \to 0} \frac{\sin(x)}{x} $$
Check the form: Direct substitution gives $\frac{\sin(0)}{0} = \frac{0}{0}$. This is indeterminate.
Apply L'Hôpital's Rule: We differentiate the numerator and denominator separately.